Match list I with List II and select the correct answer using the code given below the lists `:`
`{:("List I",,,"List II"),("(a) "SO_(2)","NO_(3)^(-)","CO_(3)^(2-),,,"(p)Semi-metals"),((b)B","Si","Ge","As","Sb,,,"(q)Isoelectronic species"),((c) He","Ne","Ar","Kr","Xe,,,"(r)Van der wall's radii"),((d) M(g)+"energy"rarr M^(+)(g)+e^(-),,,"(s)Ionisation energy"):}`
Code `:`

Options

A. `{:(,"(a)","(b)","(c)","(d)"),(,q,p,r,s):}`
B. `{:(,"(a)","(b)","(c)","(d)"),(,p,q,r,s):}`
C. `{:(,"(a)","(b)","(c)","(d)"),(,q,p,s,r):}`
D. `{:(,"(a)","(b)","(c)","(d)"),(,r,p,q,r):}`

Explanation

To solve the matching question, we will analyze each item in List I and match it with the appropriate item in List II based on their properties.

### Step-by-Step Solution:

1. **Match (a) SO₂, NO₃⁻, CO₃²⁻ with List II:**
- We need to determine if these species are isoelectronic.
- **SO₂:** Sulfur (S) has an atomic number of 16, and each oxygen (O) has an atomic number of 8. Thus, SO₂ has 16 + (2 × 8) = 32 electrons.
- **NO₃⁻:** Nitrogen (N) has an atomic number of 7, and there are three oxygens. Thus, NO₃⁻ has 7 + (3 × 8) + 1 (for the negative charge) = 32 electrons.
- **CO₃²⁻:** Carbon (C) has an atomic number of 6, and there are three oxygens. Thus, CO₃²⁻ has 6 + (3 × 8) + 2 (for the negative charge) = 32 electrons.
- Since all three species have the same number of electrons (32), they are isoelectronic.
- **Match:** (a) → (q) Isoelectronic species.

2. **Match (b) B, Si, Ge, As, Sb with List II:**
- These elements are known as metalloids, which exhibit properties of both metals and nonmetals.
- They are located between the S block and P block of the periodic table.
- **Match:** (b) → (p) Semi-metals.

3. **Match (c) He, Ne, Ar, Kr, Xe with List II:**
- These elements are noble gases.
- The radii of noble gases are determined by van der Waals radii.
- **Match:** (c) → (r) Van der Waals radii.

4. **Match (d) M(g) + energy → M⁺(g) + e⁻ with List II:**
- This reaction describes the process of ionization, where energy is supplied to remove an electron from a neutral atom.
- This process is known as ionization energy.
- **Match:** (d) → (s) Ionization energy.

### Final Matches:
- (a) → (q)
- (b) → (p)
- (c) → (r)
- (d) → (s)

### Conclusion:
The correct option is A: (a) → (q), (b) → (p), (c) → (r), (d) → (s).

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