Match List I ( atomic number of the element ) with List II ( position in the periodic table ) and select the correct answer using the codes given below the lists `-`
`{:(,List" "I,,,List" "II),((a),52,,(p),s-block),((b),56,,(q),p-block),((c ),57,,(r),d-block),((d ),60,,(s),f-block):}`

Options

A. `{:(,"(a)","(b)","(c)","(d)"),(,q,p,r,s):}`
B. `{:(,"(a)","(b)","(c)","(d)"),(,q,p,s,r):}`
C. `{:(,"(a)","(b)","(c)","(d)"),(,p,q,r,s):}`
D. `{:(,"(a)","(b)","(c)","(d)"),(,p,b,s,r):}`

Explanation

To solve the question of matching the atomic numbers with their respective positions in the periodic table, we will analyze each atomic number and determine its electronic configuration. Based on this, we can identify whether the element belongs to the s-block, p-block, d-block, or f-block of the periodic table.

### Step-by-Step Solution:

1. **Identify Atomic Number 52:**
- The element with atomic number 52 is Tellurium (Te).
- **Electronic Configuration:** The nearest noble gas is Krypton (Kr), so the electronic configuration is:
\[ [Kr] \, 4d^{10} \, 5s^2 \, 5p^4 \]
- **Position in the Periodic Table:** The last electron enters the p-orbital, so Tellurium is in the **p-block**.

2. **Identify Atomic Number 56:**
- The element with atomic number 56 is Barium (Ba).
- **Electronic Configuration:** The nearest noble gas is Xenon (Xe), so the electronic configuration is:
\[ [Xe] \, 6s^2 \]
- **Position in the Periodic Table:** The last electron enters the s-orbital, so Barium is in the **s-block**.

3. **Identify Atomic Number 57:**
- The element with atomic number 57 is Lanthanum (La).
- **Electronic Configuration:** The electronic configuration is:
\[ [Xe] \, 5d^1 \, 6s^2 \]
- **Position in the Periodic Table:** The last electron enters the d-orbital, so Lanthanum is in the **d-block**.

4. **Identify Atomic Number 60:**
- The element with atomic number 60 is Neodymium (Nd).
- **Electronic Configuration:** The electronic configuration is:
\[ [Xe] \, 4f^4 \, 6s^2 \]
- **Position in the Periodic Table:** The last electron enters the f-orbital, so Neodymium is in the **f-block**.

### Summary of Matches:
- **52 (Te)** → **p-block** (q)
- **56 (Ba)** → **s-block** (p)
- **57 (La)** → **d-block** (r)
- **60 (Nd)** → **f-block** (s)

### Final Matching:
- a → q (52 → p-block)
- b → p (56 → s-block)
- c → r (57 → d-block)
- d → s (60 → f-block)

### Correct Answer:
The correct answer based on the matching is **qprs**, which corresponds to option number **1**.