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A wedge is moving rightwards on which a ...


A wedge is moving rightwards on which a block of mass 10 kg is placed on it. Friction coefficient between the eedge and the block is 0.8. Select correct alternative (s) among the following options. [take `g=10(m)/(s^(2))`]

A

if wedge is moving with constant velocity then friction acting on block is 64N.

B

if wedge is moving with cosntant velocity then acceleration of block is zero.

C

if wedge is moving with `veca=2(veci)(m)/(s^(2))` then friction acting on block is 44N.

D

if wedge is moving with `veca=10(veci)(m)/(s^(2))` then friction is 20N. Downward on the block along the inclined.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D

(A,B) if moving with constant velocity then `a=0`
so friction available `=mumgcostheta`
`=(0.8)(10)(10)((4)/(5))=64N`.
But `mgsintheta=60N`
So required friction is 60 N.
So net force is zero.
`(C)a=2hat(i)f=mgsin37^(@)-macos37^(@)=44N`
`(D)f=mgsin37^(@)-macos37^(@)=-20N`
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