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A radioactive nucleus can decay be eithe...

A radioactive nucleus can decay be either emitting an `alpha` particle or by emitting a `beta` particle. Probability of `alpha` decay is `75%` while that of `beta` decay is `25%` the decayconstatnt of `alpha` decay is `lamda_(1)` and that of `beta` decay is `lamda_(2)` is `(lamda_(1))/(lamda_(2))`

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To solve the problem, we need to find the ratio of the decay constants \(\lambda_1\) (for alpha decay) and \(\lambda_2\) (for beta decay) based on the probabilities of each type of decay. ### Step-by-Step Solution: 1. **Understand the Given Probabilities:** - The probability of alpha decay, \(P(\alpha)\), is given as 75% or 0.75. - The probability of beta decay, \(P(\beta)\), is given as 25% or 0.25. 2. **Relate Decay Constants to Probabilities:** - The decay constant is related to the probability of decay. The ratio of the decay constants can be expressed in terms of the probabilities: \[ \frac{\lambda_1}{\lambda_2} = \frac{P(\alpha)}{P(\beta)} \] 3. **Substitute the Values:** - Substitute the values of the probabilities into the equation: \[ \frac{\lambda_1}{\lambda_2} = \frac{0.75}{0.25} \] 4. **Calculate the Ratio:** - Simplifying the fraction: \[ \frac{0.75}{0.25} = 3 \] 5. **Final Result:** - Therefore, the ratio of the decay constants is: \[ \frac{\lambda_1}{\lambda_2} = 3 \] ### Conclusion: The ratio of the decay constants \(\frac{\lambda_1}{\lambda_2}\) is 3. ---

To solve the problem, we need to find the ratio of the decay constants \(\lambda_1\) (for alpha decay) and \(\lambda_2\) (for beta decay) based on the probabilities of each type of decay. ### Step-by-Step Solution: 1. **Understand the Given Probabilities:** - The probability of alpha decay, \(P(\alpha)\), is given as 75% or 0.75. - The probability of beta decay, \(P(\beta)\), is given as 25% or 0.25. ...
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