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Pb|PbSO(4)|H(2)SO(4)(aq)||PbCl(2) satura...

`Pb|PbSO_(4)|H_(2)SO_(4)(aq)||PbCl_(2)` saturated solution `|Cl_(2)|Pt` As the cell discharged:

A

Conductivity of anode solution decreases

B

Concentration of `Pb^(2+)` increases at anode solution and decreases at cathode

C

`E_("cell")^(@)` depends on `K_(sp)` of `PbSO_(4)` and `K_(sp)` of `PbCl_(2)`

D

`E_("cell")^(@)` is zero

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The correct Answer is:
To solve the problem regarding the cell representation and its behavior during discharge, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Identify the Reactions at the Electrodes:** - At the **anode**, the oxidation reaction occurs: \[ \text{Pb (s)} + \text{SO}_4^{2-} \rightarrow \text{PbSO}_4 (s) + 2 \text{e}^- \] - At the **cathode**, the reduction reaction occurs: \[ \text{Cl}_2 (g) + 2 \text{e}^- \rightarrow 2 \text{Cl}^- \] 2. **Analyze the Changes in Concentration:** - **At the anode:** As lead (Pb) is oxidized to lead sulfate (PbSO4), the concentration of sulfate ions (SO4^2-) decreases. This decrease in sulfate ions leads to a decrease in the conductivity of the anode solution. - **At the cathode:** Chlorine gas (Cl2) is reduced to chloride ions (Cl^-). The chloride ions then react with lead ions (Pb^2+) to form solid lead chloride (PbCl2). As a result, the concentration of lead ions (Pb^2+) decreases at the cathode. 3. **Evaluate the Options:** - **Option A:** The conductivity of the anode solution decreases. This is correct because the concentration of sulfate ions decreases. - **Option B:** The concentration of lead ions increases at the anode and decreases at the cathode. This is also correct. The concentration of sulfate ions decreases at the anode, which causes the lead ion concentration to increase to maintain the solubility product (Ksp). - **Option C:** E° cell depends upon Ksp of PbSO4 and Ksp of PbCl2. This is correct; the standard cell potential (E°) is influenced by the solubility products of the compounds involved. - **Option D:** E° cell is zero. This is incorrect because the cell potential cannot be zero under normal conditions. 4. **Conclusion:** - The correct statements when the cell is discharged are options A, B, and C. ### Final Answer: - **Correct Options:** A, B, C

To solve the problem regarding the cell representation and its behavior during discharge, we will analyze each option step by step. ### Step-by-Step Solution: 1. **Identify the Reactions at the Electrodes:** - At the **anode**, the oxidation reaction occurs: \[ \text{Pb (s)} + \text{SO}_4^{2-} \rightarrow \text{PbSO}_4 (s) + 2 \text{e}^- ...
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