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The K(a) of monobasic acid P, Q and R ar...

The `K_(a)` of monobasic acid `P, Q` and R are `10^(-6),10^(-8)` and `10^(-10)` respectively. The concentrations of P, Q and R are respectively
0.1M, 0.01 M and 0.001 M .
Q. Which acid has the minimum pH?

A

P

B

Q

C

R

D

All have equal pH

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The correct Answer is:
To determine which acid (P, Q, or R) has the minimum pH, we need to analyze the given information about their dissociation constants (K_a) and concentrations. ### Step-by-Step Solution: 1. **Identify the given values**: - For acid P: \( K_a = 10^{-6} \) and concentration = 0.1 M - For acid Q: \( K_a = 10^{-8} \) and concentration = 0.01 M - For acid R: \( K_a = 10^{-10} \) and concentration = 0.001 M 2. **Understand the relationship between \( K_a \) and acidity**: - The larger the \( K_a \), the stronger the acid, which means it dissociates more in solution and produces more hydrogen ions (\( H^+ \)). - Therefore, the acid with the highest \( K_a \) will have the lowest pH. 3. **Calculate the concentration of \( H^+ \) ions for each acid**: - For a weak acid, the dissociation can be represented as: \[ HA \rightleftharpoons H^+ + A^- \] The expression for \( K_a \) is: \[ K_a = \frac{[H^+][A^-]}{[HA]} \] - Assuming \( x \) is the concentration of \( H^+ \) produced, we can write: \[ K_a = \frac{x^2}{[HA] - x} \approx \frac{x^2}{[HA]} \quad \text{(for weak acids, where } x \text{ is small compared to } [HA]) \] 4. **Calculate \( H^+ \) concentration for each acid**: - For acid P: \[ K_a = 10^{-6} = \frac{x^2}{0.1} \implies x^2 = 10^{-6} \times 0.1 = 10^{-7} \implies x = 10^{-3} \, \text{M} \] - For acid Q: \[ K_a = 10^{-8} = \frac{x^2}{0.01} \implies x^2 = 10^{-8} \times 0.01 = 10^{-10} \implies x = 10^{-5} \, \text{M} \] - For acid R: \[ K_a = 10^{-10} = \frac{x^2}{0.001} \implies x^2 = 10^{-10} \times 0.001 = 10^{-13} \implies x = 10^{-6.5} \, \text{M} \] 5. **Determine the pH for each acid**: - pH is calculated using the formula: \[ \text{pH} = -\log[H^+] \] - For acid P: \[ \text{pH} = -\log(10^{-3}) = 3 \] - For acid Q: \[ \text{pH} = -\log(10^{-5}) = 5 \] - For acid R: \[ \text{pH} = -\log(10^{-6.5}) \approx 6.5 \] 6. **Compare the pH values**: - pH of P = 3 - pH of Q = 5 - pH of R ≈ 6.5 7. **Conclusion**: - The acid with the minimum pH is acid P, which has the highest \( K_a \) value. ### Final Answer: **Acid P has the minimum pH.**
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