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How many of the following pairs are conj...

How many of the following pairs are conjugate acid/base pairs?
`HCl,Cl^(-)`
`KH,KCl`
`H_(2)SO_(4),Na_(2)SO_(4)`
`NaHS,Na_(2)S`
`CH_(3)COOH,CH_(3)COOH_(2)^(+)`
`Na_(2)CO_(3),NaHCO_(3)`
`NH_(3),NH_(4)Br`
`HCl,ClOH`
Aniline, anilinium

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The correct Answer is:
To determine how many of the given pairs are conjugate acid/base pairs, we need to understand the concept of conjugate acids and bases. According to the Brønsted-Lowry theory, an acid is a proton donor and a base is a proton acceptor. When an acid donates a proton (H⁺), it becomes its conjugate base, and when a base accepts a proton, it becomes its conjugate acid. Let's analyze each pair: 1. **HCl, Cl⁻**: - HCl donates a proton to become Cl⁻. - **Conjugate pair**: Yes. 2. **KH, KCl**: - KH is a salt that does not act as an acid or base in this context. KCl is a neutral salt and does not have a conjugate acid/base relationship. - **Conjugate pair**: No. 3. **H₂SO₄, Na₂SO₄**: - H₂SO₄ is a strong acid, while Na₂SO₄ is a salt. They do not have a direct acid/base relationship. - **Conjugate pair**: No. 4. **NaHS, Na₂S**: - NaHS can act as a weak acid (donating H⁺) to become Na₂S, which does not have a corresponding acid/base relationship. - **Conjugate pair**: No. 5. **CH₃COOH, CH₃COOH₂⁺**: - CH₃COOH (acetic acid) can donate a proton to become CH₃COO⁻ (its conjugate base), but CH₃COOH₂⁺ is not the conjugate base of CH₃COOH. - **Conjugate pair**: No. 6. **Na₂CO₃, NaHCO₃**: - Na₂CO₃ can donate a proton to become NaHCO₃. NaHCO₃ can accept a proton to become H₂CO₃. - **Conjugate pair**: Yes. 7. **NH₃, NH₄Br**: - NH₃ is a base that can accept a proton to become NH₄⁺ (ammonium ion). NH₄Br is a salt and does not represent a conjugate acid/base relationship. - **Conjugate pair**: No. 8. **HCl, ClOH**: - HCl donates a proton to become Cl⁻, while ClOH is not a direct conjugate of HCl. - **Conjugate pair**: No. 9. **Aniline, Anilinium**: - Aniline (C₆H₅NH₂) can accept a proton to become anilinium ion (C₆H₅NH₃⁺). - **Conjugate pair**: Yes. Now, let's summarize the results: - Pairs that are conjugate acid/base pairs: 1. HCl, Cl⁻ 2. Na₂CO₃, NaHCO₃ 3. Aniline, Anilinium Thus, there are **3 conjugate acid/base pairs** in total.
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