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Two uniform solid cylinders A and B each...

Two uniform solid cylinders A and B each of mass 1 kg are connected by a spring of constant `200Nm^(-1)` at their axles and are placed on a fixed wedge as shown in fig.There is no friction between cylinders and wedge. The angle made by the line AB with the horizontal, in equilibirum is

A

`0^(@)`

B

`45^(@)`

C

`30^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

`mgsin60^(@)=kxcos(60^(@)-theta)` .(1)
`mgsin30^(@)=kxcos(30+theta)` .(2)
`=kxsin((pi)/(theta)-(30+theta))`
`=kxsin(60^(@)-theta)` … (3)
From (1) and (3)
`tan(60^(@)-theta)=(sin30^(@))/(sin60^(@))=(1)/(sqrt(3))impliestheta=30^(@)`
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