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A block of mass m is pulled slowly by a ...

A block of mass `m` is pulled slowly by a minimum constant force `(F)` on a horizontal surface thorugh a distance x. The coefficient of kinetic friciton is `mu`. Find the work done by the force `(F)`.

A

`(mgx)/(sqrt(1+mu^(2)))`

B

`(mumgx)/(1+mu^(1))`

C

`(mu^(2)mgx)/(sqrt(1+mu^(2)))`

D

`(mgx)/((1+mu^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B

Work`=mgsinthetacosthetaxx x`
`=xmg((mu)/(sqrt(1+mu^(2))))(1)/(sqrt(1+mu^(2)))=(mumgx)/(1+mu^(2))`
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