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A small element l is cut from a ciruclar...

A small element `l` is cut from a ciruclar ring of radius `a` and `lambda` charge per unit length. The net electric field at the centre of ring is

A

`E=(K(lamda)dl)/(R^(2))` (towards `-x`)

B

`E=(K(lamda)dl)/(R^(2))` (towards `+x`)

C

`E=(Klamdadl)/(2R^(2))` (towards `-x`)

D

`E=(Klamdadl)/(2R^(2))` (towards `+x`)

Text Solution

Verified by Experts

The correct Answer is:
B

`(k(Q))/(R^(2))=(-Klamdadl)/(R^(2))`
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