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The electrode potentials for Cu^(2+) ...

The electrode potentials for
` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) `
and ` Cu^+ (aq) + e^(-) rarr Cu (s)`
are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(Cu^(2+)//Cu)^@` will be.

A

0.500 V

B

0.325 V

C

0.650 V

D

0.150 V

Text Solution

Verified by Experts

The correct Answer is:
B
`Cu^(2+)+1e^(-)toCu^(+)` `E_(1)^(0)=0.15vDeltaG_(1)^(0)=-n_(7)E_(1)^(0)F`
underline(Cu^(+)+e^(-)toCu_(s) E_(2)^(0)=0.50vDeltaG_(2)^(0)=-n_(7)E_(2)^(0)F)`
`Cu^(2+)+2e^(-)toCuDeltaG^(@)=DeltaG_(1)^(@)+DeltaG_(2)^(@)`
`(-1)nEF=(-1)n_(1)E_(1)^(0)F+(-1)n_(2)E_(2)^(0)F`
`E=(n_(1)E_(1)^(0)+n_(2)E_(2)^(0))/(n)=(0.15xx1+0.50xx1)/(2)=0.325V`
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