Carbonyl compound (p)
`underset((2). H_(2)O)overset((1). "grignard reagent")toPh-CH_(2)-underset(OH)underset(|)overset(H)overset(|)C-CH_(3)`
Carbonyl compound can be:

Options

A. `Ph-CH_(2)-underset(O)underset(||)C-CH_(3)`
B. `Ph-CH_(2)-CH=O`
C. `CH_(3)-CH_(2)-CH=O`
D. `CH_(3)-underset(O)underset(||)C-CH_(3)`

Explanation

To solve the problem, we need to identify the carbonyl compound (P) that reacts with a Grignard reagent to produce the given product. Let's break down the steps:

### Step 1: Identify the Product Structure
The product is represented as:
- Ph-CH₂-C(OH)-CH₃

From this structure, we can see that it contains:
- A phenyl group (Ph)
- A hydroxyl group (OH)
- An alkyl chain with a methyl group (CH₃)

### Step 2: Determine the Type of Alcohol
The product has a hydroxyl group (OH) attached to a carbon that is also connected to two other carbon atoms (one being part of the phenyl group and the other being a methyl group). This indicates that the product is a secondary alcohol.

### Step 3: Analyze the Grignard Reagent Reaction
The Grignard reagent (let's assume it is CH₃MgBr) will act as a nucleophile. It will attack the carbonyl carbon of compound P, which must be either an aldehyde or a ketone.

### Step 4: Consider Possible Carbonyl Compounds
1. **Aldehyde:** If P is an aldehyde, the reaction with CH₃MgBr would lead to a secondary alcohol.
- Example: If P is benzaldehyde (Ph-CHO), the reaction would yield:
- Ph-CH₂-CH(OH)-CH₃

2. **Ketone:** If P is a ketone, the reaction would lead to a tertiary alcohol.
- Example: If P is acetophenone (Ph-CO-CH₃), the reaction would yield:
- Ph-CH₂-C(OH)(CH₃)-CH₃

### Step 5: Determine the Correct Carbonyl Compound
Since the product is a secondary alcohol, we conclude that the carbonyl compound P must be an aldehyde.

### Conclusion
The carbonyl compound (P) can be identified as an aldehyde, specifically benzaldehyde (Ph-CHO).