Ethylester `underset("excess")overset(CH_(3)CH_(2)MgBr)toP`. The product P will be

Options

A. `CH_(3)underset(OH)underset(|)overset(C_(2)H_(5))overset(|)C-CH_(3)`
B. `CH_(3)-underset(OH)underset(|)overset(CH_(3))overset(|)C-CH_(3)`
C. `CH_(3)-underset(OH)underset(|)overset(C_(2)H_(5))overset(|)C-C_(2)H_(5)`
D. `CH_(3)-underset(OH)underset(|)overset(H)overset(|)C-C_(2)H_(5)`

Explanation

To solve the problem of determining the product P when ethyl ester is treated with excess CH₃CH₂MgBr (ethyl magnesium bromide), we can follow these steps:

### Step 1: Identify the Reactants
The reactant is ethyl ester, which can be represented as CH₃CH₂OCOCH₃ (ethyl acetate). The Grignard reagent is CH₃CH₂MgBr.

### Step 2: Nucleophilic Attack
The Grignard reagent (CH₃CH₂MgBr) acts as a nucleophile and will attack the carbonyl carbon of the ethyl ester. This results in the formation of a tetrahedral intermediate. The reaction can be illustrated as follows:

1. The nucleophilic ethyl group (CH₃CH₂-) attacks the carbonyl carbon (C=O) of the ester.
2. The double bond between carbon and oxygen breaks, leading to the formation of a new bond between the carbon of the Grignard reagent and the carbonyl carbon of the ester.

### Step 3: Formation of an Intermediate
After the nucleophilic attack, we get an intermediate product:

\[ \text{CH}_3\text{C(OH)(C}_2\text{H}_5)\text{O} \]

Additionally, we release ethanol (C₂H₅OH) as a byproduct.

### Step 4: Second Nucleophilic Attack
Since we have excess Grignard reagent, a second nucleophilic attack occurs. The hydroxyl group (OH) from the intermediate can be further attacked by another molecule of CH₃CH₂MgBr. This leads to the formation of another carbon-carbon bond:

1. The ethyl group from the Grignard reagent attacks the carbon of the hydroxyl group.
2. This results in the formation of a new carbon-carbon bond.

### Step 5: Final Product Formation
After the second attack, we will have a tertiary alcohol, which can be represented as:

\[ \text{CH}_3\text{C(OH)(C}_2\text{H}_5)(C}_2\text{H}_5) \]

After hydrolysis, the final product P will be:

\[ \text{CH}_3\text{C(OH)(C}_2\text{H}_5)(C}_2\text{H}_5) \]

This compound is 1,1-diethyl-2-propanol.

### Conclusion
The final product P formed from the reaction of ethyl ester with excess CH₃CH₂MgBr is a tertiary alcohol.