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A wedge B of mass 2 m is placed on a rou...


A wedge `B` of mass 2 m is placed on a rough horizontal suface. The coefficient of friction between wedge and the horizontal surface is `mu_(1)`. A block of mass m is placed on wedge as shown in the figure. The coefficient of friction between block and wedge is `mu_(2)`. The block and wedge are released from rest.
Q. Suppose the inclined surface of the wedge is at `theta=37^(@)` from angle from horizontal and `mu_(2)=0` are wedge will remain in equilibrium if

A

`mu_(1)=0.1`

B

`mu_(1)=0.2`

C

`mu_(1)=0.3`

D

`mu_(1)=0.4`

Text Solution

Verified by Experts

The correct Answer is:
B, C, D

`FBD` of wedge
`Nsin37^(@)=mu_(1)(2mg+Ncos37^(@))`
`mgcos37^(@)sin37^(@)=mu(2mg+mgcos^(2)37^(@))`
`(12)/(25)=mu_(1)(1+(16)/(25))`
`mu_(1)=(12)/(66)=(2)/(11)`
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