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In the given figure, the object is place...

In the given figure, the object is placed at the centre of curvature of the mirror. Find the instantaneous velocity of image at the shown instant (in cm/s)

Text Solution

Verified by Experts

The correct Answer is:
5

`vecV_(im)=-(v^(2))/(u^(2))vecv_(om)`
`0-(40)/(13)=-((-10)/(-10+x))^(2)(10-(40)/(13))`
`(-10)/(-10+x)=+-(2)/(3)`
`x=25,-5cm`
Object is infront of mirror
Hence `25cm`
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