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In the given circuit, in steady state we...

In the given circuit, in steady state we may say: (capacitors are initially unchanged)

A

potential drop across the capacitor `c_(1)` is `4v`

B

potential drop across `10 Omega` resistance 10 v

C

charge on `C_(1)` and `C_(2)` is `20muC`

D

ratio of charge on `C_(1)` and `C_(2)` is 1

Text Solution

Verified by Experts

The correct Answer is:
A, D

`C_(eq)=(10xx4)/(10+4)=(40)/(14)`
`Q=C_(eq)C=(40)/(14)xx14=40muC`
`V_(c1)=(40)/(10)=4v`
`V_(c2)=(40)/(4)=10v`.
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