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In the given LR circuit, the switch S is...

In the given LR circuit, the switch S is closed at the t=0 Then.

A

The ratio of induced emfs in the inductors of inductance L and 2L will be constant

B

The ratio of induced emfs in the inductor of inductance L and 2L will be time varying

C

the potential difference `V_(A)-V_(B)` increases with time

D

The potential difference `V_(A)-V_(B)` will be constant

Text Solution

Verified by Experts

The correct Answer is:
A, D

`i_(1)=(epsi)/(R)(1-e^((-Rt)/(L)))`
`i_(2)=(epsi)/(2R)(1-e^((-R)/(L)t))`
`(epsi_("ind")_(L)=L(di_(i))/(dt)=epsie^(-(Rt)/(L))`
`(epsi_("ind")_(2L)=2L(di_(2))/(dt)=epsi(e^(-(Rt)/(L)t)`
`((epsi_("ind"))_(L))/((epsi_("ind"))2L)=1`
`V_(A)-V_(B)=0=` cosntant
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