`alpha` -maltose can be hydrolysed to glucose according to the following reaction:
`alpha - C_(12)H_(22)O_(11) (aq) + H_(2)O(l) rarr 2C_(6)H_(12)O_(6)(aq)`
Given standard enthalpy of formation of `H_(2)O(l) , C_(6)H_(12)O_(6)(aq) and C_(12)H_(22)O_(11)` are and `-285, -1263 and -2238 kJ//mol` respectively. Which of the following statements is (are) true?

Options

A. the hydrolysis of `alpha`- maltose is exothermic.
B. Heat liberated in combustion of 1.0 mol of `alpha`- moltose is greater than the heat liberated in combustion of 2.0 mol of glucose.
C. Increasing temperature will increase the degree of hydrolysis of `alpha`- maltose
D. The hydrolysis of `alpha`- maltose follow `1^(st)` order kinetics.

Answer

A, B, D

Explanation

(A). `DeltaH=[2(-1263)]-[(-2238)+(-285)]=-3kJ`
(B). `C_(12)H_(22)O_(11)+12O_(2)to12CO_(2)+11H_(2)O`
`{C_(6)H_(12)O_(6)6O_(2)to6CO_(2)+6H_(2)O}xx2`
`C_(12)H_(22)O_(11)+H_(2)Oto2C_(6)H_(12)O_(5),DeltaH=-3kJ` ltbr. (C). Hydrolysis is exothermic `Tuarrhdarr`
(D). Concentration becomes one-fourth in equal tim interval. Hence `1^(st)` order.