The xenate ion `(HXeO_(4)^(-))` undergoes disproportionation reaction to produce perxenate ion `XeO_(5)^(4-)`
`2HXeO_(4)^(-)+2OH^(-)toXeO_(6)^(4-)+Xe+O_(2)+2H_(2)O`
The shape of xenate ion and perxenate ions is respectively:

Options

A. Pyramidal & square planar
B. Tetrahedral & octahedral
C. See- saw & octahedral
D. Tetrahedral & Square planar

Explanation

To determine the shapes of the xenate ion (HXeO₄⁻) and the perxenate ion (XeO₅⁴⁻), we can follow these steps:

### Step 1: Analyze the Xenate Ion (HXeO₄⁻)
1. **Identify the central atom**: The central atom in the xenate ion is xenon (Xe).
2. **Determine the steric number**:
- Xenon has 8 valence electrons.
- The hydrogen contributes 1 electron.
- The negative charge adds 1 electron.
- Total = 8 (Xe) + 1 (H) + 1 (charge) = 10 electrons.
- Each bond with oxygen counts as 1, and lone pairs count as 1.
- The xenate ion has 4 oxygen atoms bonded to xenon and 1 lone pair.
- Therefore, the steric number = (10 electrons) / 2 = 5.
3. **Determine the geometry**:
- A steric number of 5 corresponds to a trigonal bipyramidal geometry.
4. **Identify the shape**:
- The presence of a lone pair alters the shape from trigonal bipyramidal to see-saw.
- Therefore, the shape of the xenate ion is **see-saw**.

### Step 2: Analyze the Perxenate Ion (XeO₅⁴⁻)
1. **Identify the central atom**: The central atom in the perxenate ion is also xenon (Xe).
2. **Determine the steric number**:
- Again, xenon has 8 valence electrons.
- The negative charge contributes 4 electrons.
- Total = 8 (Xe) + 4 (charge) = 12 electrons.
- Each bond with oxygen counts as 1.
- The perxenate ion has 5 oxygen atoms bonded to xenon.
- Therefore, the steric number = (12 electrons) / 2 = 6.
3. **Determine the geometry**:
- A steric number of 6 corresponds to an octahedral geometry.
4. **Identify the shape**:
- The shape of the perxenate ion is **octahedral**.

### Summary of Shapes
- The shape of the xenate ion (HXeO₄⁻) is **see-saw**.
- The shape of the perxenate ion (XeO₅⁴⁻) is **octahedral**.