Which of the following is/are correct name for the give polymer?

Options

A. Polypropene
B. Polystyrene
C. .Urea-formaldehyde Resin
D. Bakelite

Explanation

To determine which of the given options are correct names for the specified polymer, we will analyze each option step by step.

### Step 1: Analyze Option A - Polypropene
- **Structure**: The monomer for polypropene is propene, which has the structure CH2=CH-CH3.
- **Polymer Formation**: When propene undergoes polymerization, it forms polypropene, which is represented as (C3H6)n.
- **Conclusion**: Since the structure corresponds to polypropene, **Option A is correct**.

### Step 2: Analyze Option B - Polystyrene
- **Structure**: The monomer for polystyrene is styrene, which has the structure CH2=CH-C6H5.
- **Polymer Formation**: When styrene polymerizes, it forms polystyrene, represented as (C8H8)n.
- **Conclusion**: The structure corresponds to polystyrene, so **Option B is correct**.

### Step 3: Analyze Option C - Urea Formaldehyde Resin
- **Monomers**: The monomers for urea formaldehyde resin are urea (NH2-C(=O)-NH2) and formaldehyde (HCHO).
- **Polymer Formation**: When urea and formaldehyde react, they undergo a condensation reaction to form the polymer, releasing water. The structure of the polymer can be represented as:
- NH-C(=O)-NH-CH2-NH-C(=O)-NH-...
- **Conclusion**: The structure corresponds to urea formaldehyde resin, thus **Option C is correct**.

### Step 4: Analyze Option D - Bakelite
- **Monomers**: Bakelite is formed from the condensation of phenol (C6H5OH) and formaldehyde (HCHO).
- **Polymer Formation**: The structure of Bakelite is complex and involves multiple phenolic and methylene linkages. It does not correspond to a simple linear polymer but rather a cross-linked structure.
- **Conclusion**: The structure does not match the typical representation of Bakelite, so **Option D is incorrect**.

### Final Conclusion
The correct names for the given polymer are **A, B, and C**.

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