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A uniform conducting ring of mass pi kg ...

A uniform conducting ring of mass `pi` kg and radiius 1m is kept on a smooth horizontal table, A uniform but time varying magnetic field T is present in the region where is in second and the positive y-axis is in vertically upward direction, `(g=10m//s^(2))`. Resistance of the ring in `2Omega`.

Time at which rings starts toppling is

A

`(10)/(pi)sec`

B

`(20)/(pi)sec`

C

`(5)/(pi)sec`

D

`(5)/(pi)sec`

Text Solution

Verified by Experts

The correct Answer is:
A
`I=(1)/(R)|(dphi)/(dt)|=(1)/(2)pixx1^(2)::2t=pit`
The ring will start toppling when
`tau_(m)=tau_(g)`
`impliesIAB_(x)=mgr`
`impliespitxxpixx1^(2)xx1=pixx10xx1`
`impliest=(10)/(pi)sec`
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