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(i) P+C("carbon")+Cl(2) to Q+CO uaarr ...

(i) `P+C("carbon")+Cl_(2) to Q+CO uaarr`
(ii) `Q+H_(2)O to R+HCl`
(iii) `BN+H_(2)O to R+NH_(3) uarr`
(iv) `Q+LiAlH_(4) to S+LiCl+AlCl_(3)`
(v) `S+H_(2) to R+H_(2) uarr`
(vi) `S+NaH to T`
(P,Q,R,S annd T do not represent their chemical symbols)
Q. Compound Q has:
(I) zero dipole moment.
(II) a planar trigonal structure
(III) an electron deficient compound
(IV) a lewis base
Chose the correct code:

A

I,IV

B

I,II,IV

C

I,II,III

D

I,II,III,IV

Text Solution

Verified by Experts

The correct Answer is:
C
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(i) P+C("carbon")+Cl_(2) to Q+CO uaarr (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound T is used as a/an:

(i) P+C("carbon")+Cl_(2)toQ+CO uarr , (ii) Q+H_(2)OtoR+HCl (iii) BN+H_(2)O to R+NH_(3) , (iv) Q+LiAIH_(4) to S+LiCl+ AlCl_(3) (v) S+H_(2)toR+H_(2) uarr , (vi) S+NaH to T ( P,Q,R,S and T do not represent their chemical symbols) Compound S is

(i) P+C("carbon")+Cl_(2) to Q+CO (ii) Q+H_(2)O to R+HCl (iii) BN+H_(2)O to R+NH_(3) uarr (iv) Q+LiAlH_(4) to S+LiCl+AlCl_(3) (v) S+H_(2) to R+H_(2) uarr (vi) S+NaH to T (P,Q,R,S annd T do not represent their chemical symbols) Q. Compound S is: (I) an odd e^(-) compound (II) (2c-3e^(-)) compound (III) a electron deficient compound (IV) a sp^(2) hybridized compound Choose the correct code:

NaH(s)+H_(2)O to NaOH+H_(2)uarr

Na(s)+H_(2)O(l) overset(R.T.) to NaOH +H_(2) uarr

Na(s)+H_(2)O(l) overset(R.T.) to NaOH +H_(2) uarr

P Q R S is a square. P R and S Q intersect at Odot State the measure of /_P O Qdot

P Q R S is a square. P R and S Q intersect at Odot State the measure of /_P O Qdot

P Q R S is a square such that P R\ a n d\ S Q intersect at O . State the measure of /_P O Q .

Consider following reaction: Cl_(2)(g)+H_(2)O overset(R.T.)to P+Q If molecular weight of P is less than Q then incorrect statement is:

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