When `P_(4)O_(10)` is dissolved in water, the acid formed finally is :

Options

A. `H_(3)PO_(2)`
B. `H_(3)PO_(4)`
C. `H_(3)PO_(3)`
D. `H_(3)PO_(4)`

Answer

To determine the acid formed when \( P_4O_{10} \) is dissolved in water, we can follow these steps:

### Step 1: Identify the Reaction
When \( P_4O_{10} \) (tetraphosphorus decoxide) is dissolved in water, it reacts to form an acid. The reaction can be represented as:
\[ P_4O_{10} + H_2O \rightarrow H_3PO_4 \]

### Step 2: Write the Balanced Equation
The balanced chemical equation for the reaction is:
\[ P_4O_{10} + 6H_2O \rightarrow 4H_3PO_4 \]
This indicates that one mole of \( P_4O_{10} \) reacts with six moles of water to produce four moles of phosphoric acid (\( H_3PO_4 \)).

### Step 3: Identify the Product
From the balanced equation, we can see that the product formed is phosphoric acid (\( H_3PO_4 \)).

### Conclusion
Thus, when \( P_4O_{10} \) is dissolved in water, the final acid formed is phosphoric acid (\( H_3PO_4 \)).

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