The atomic number of an element is 32 and the mass number is 73. The number of electrons in the outer most shell is:

Answer

To find the number of electrons in the outermost shell of the element with atomic number 32 and mass number 73, we can follow these steps:

### Step 1: Identify the Element
The atomic number of the element is 32. This corresponds to the element Germanium (Ge) on the periodic table.

### Step 2: Determine the Electronic Configuration
To find the electronic configuration of Germanium (atomic number 32), we fill the orbitals according to the Aufbau principle. The electronic configuration is:
- 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p²

### Step 3: Identify the Outermost Shell
The outermost shell for Germanium is the fourth shell (n=4). In this shell, we have the 4s and 4p orbitals.

### Step 4: Count the Electrons in the Outermost Shell
In the outermost shell (n=4):
- The 4s orbital has 2 electrons.
- The 4p orbital has 2 electrons.

Adding these together:
- Total electrons in the outermost shell = 2 (from 4s) + 2 (from 4p) = 4 electrons.

### Conclusion
The number of electrons in the outermost shell of the element with atomic number 32 is **4**.

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