Complete and balance the following :
(i)`P_(4)O_(10)+PCl_(5)to`

Answer

To complete and balance the reaction between \( P_4O_{10} \) and \( PCl_5 \), we will follow these steps:

### Step 1: Write the unbalanced equation
The reactants are \( P_4O_{10} \) and \( PCl_5 \). The product formed is \( POCl_3 \) (phosphoryl chloride). Thus, the unbalanced equation is:
\[ P_4O_{10} + PCl_5 \rightarrow POCl_3 \]

### Step 2: Determine the number of atoms in reactants and products
- In \( P_4O_{10} \), we have:
- 4 phosphorus (P) atoms
- 10 oxygen (O) atoms

- In \( PCl_5 \), we have:
- 1 phosphorus (P) atom
- 5 chlorine (Cl) atoms

- In \( POCl_3 \), we have:
- 1 phosphorus (P) atom
- 1 oxygen (O) atom
- 3 chlorine (Cl) atoms

### Step 3: Balance phosphorus (P) atoms
From \( P_4O_{10} \), we have 4 P atoms. To balance the phosphorus, we need 4 \( POCl_3 \):
\[ P_4O_{10} + PCl_5 \rightarrow 4 POCl_3 \]

### Step 4: Balance chlorine (Cl) atoms
Each \( POCl_3 \) has 3 Cl atoms, so for 4 \( POCl_3 \), we need:
\[ 4 \times 3 = 12 \text{ Cl atoms} \]
To provide these 12 Cl atoms, we need 12 \( PCl_5 \):
\[ P_4O_{10} + 12 PCl_5 \rightarrow 4 POCl_3 \]

### Step 5: Balance the oxygen (O) atoms
In \( P_4O_{10} \), we have 10 O atoms. The product \( 4 POCl_3 \) does not contain any oxygen, so we need to ensure that the oxygen is balanced. Since \( PCl_5 \) does not contain oxygen, we need to keep \( P_4O_{10} \) as is.

### Step 6: Write the balanced equation
Now we can write the complete and balanced equation:
\[ P_4O_{10} + 6 PCl_5 \rightarrow 4 POCl_3 \]

### Final Balanced Equation
The final balanced equation is:
\[ P_4O_{10} + 6 PCl_5 \rightarrow 4 POCl_3 \]