Complete and balance the following
`NH_(3)+NaOCl to `

Answer

To complete and balance the reaction between ammonia (NH₃) and sodium hypochlorite (NaOCl), we can follow these steps:

### Step 1: Write the unbalanced equation
The initial reaction can be written as:
\[ \text{NH}_3 + \text{NaOCl} \rightarrow \text{Products} \]

### Step 2: Identify the products
When ammonia reacts with sodium hypochlorite, it typically forms hydrazine (N₂H₄), sodium chloride (NaCl), and water (H₂O). Therefore, we can propose the products as:
\[ \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \]

### Step 3: Write the unbalanced product equation
Now we can write the unbalanced equation:
\[ \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \]

### Step 4: Balance the equation
To balance the equation, we need to ensure that the number of each type of atom is the same on both sides.

1. **Nitrogen (N)**:
- Left side: 1 (from NH₃)
- Right side: 2 (from N₂H₄)
- To balance nitrogen, we need 2 NH₃:
\[ 2 \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \]

2. **Sodium (Na)**:
- Left side: 1 (from NaOCl)
- Right side: 1 (from NaCl)
- Sodium is already balanced.

3. **Chlorine (Cl)**:
- Left side: 1 (from NaOCl)
- Right side: 1 (from NaCl)
- Chlorine is already balanced.

4. **Hydrogen (H)**:
- Left side: 6 (from 2 NH₃, 2 × 3 = 6)
- Right side: 4 (from N₂H₄) + 2 (from H₂O) = 6
- Hydrogen is already balanced.

5. **Oxygen (O)**:
- Left side: 1 (from NaOCl)
- Right side: 1 (from H₂O)
- Oxygen is already balanced.

### Final balanced equation
The balanced equation is:
\[ 2 \text{NH}_3 + \text{NaOCl} \rightarrow \text{N}_2\text{H}_4 + \text{NaCl} + \text{H}_2\text{O} \]