1 mol of `H_(3)PO_(2), H_(3)PO_(3)` and `H_(3)PO_(4)` will neutralise x mol `NaOH`, y mol of `Ca(OH)_(2)` and z mol of `Al(OH)_(3)` respectively (assuming all as strong electrolytes). x, y, z are in the ratio of:

Options

A. `3:1.5:1`
B. `1:2:3`
C. `3:2:1`
D. `1:1:1`

Explanation

To solve the problem, we need to determine the number of moles of NaOH, Ca(OH)₂, and Al(OH)₃ that will be neutralized by 1 mole of H₃PO₂, H₃PO₃, and H₃PO₄ respectively.

### Step-by-Step Solution:

1. **Identify the type of acid:**
- H₃PO₂ (Phosphorous acid) is a monobasic acid because it can donate one proton (H⁺).
- H₃PO₃ (Phosphoric acid) is a dibasic acid because it can donate two protons (H⁺).
- H₃PO₄ (Phosphoric acid) is a tribasic acid because it can donate three protons (H⁺).

2. **Determine the neutralization with NaOH:**
- For H₃PO₂:
- Since it is monobasic, it can neutralize 1 mole of NaOH.
- Therefore, \( x = 1 \) mole of NaOH.

3. **Determine the neutralization with Ca(OH)₂:**
- For H₃PO₃:
- Since it is dibasic, it can neutralize 2 moles of NaOH or 1 mole of Ca(OH)₂ (which also provides 2 OH⁻ ions).
- Therefore, \( y = 1 \) mole of Ca(OH)₂.

4. **Determine the neutralization with Al(OH)₃:**
- For H₃PO₄:
- Since it is tribasic, it can neutralize 3 moles of NaOH or 1.5 moles of Ca(OH)₂, but we are looking at Al(OH)₃ which provides 3 OH⁻ ions.
- Therefore, \( z = 1 \) mole of Al(OH)₃.

5. **Establish the ratio:**
- We have found that:
- \( x = 1 \)
- \( y = 1 \)
- \( z = 1 \)
- Therefore, the ratio \( x : y : z = 1 : 1 : 1 \).

### Final Answer:
The ratio of \( x, y, z \) is \( 1 : 1 : 1 \).