Alkaline `KI`is oxidised by ozone to :

Options

A. potassium iodate
B. potassium periodate
C. both (A) and (B)
D. None of these

Answer

To solve the question regarding the oxidation of alkaline KI (potassium iodide) by ozone, we will follow these steps:

### Step 1: Identify the reactants and products
We start with potassium iodide (KI) as the reactant and ozone (O3) as the oxidizing agent. The products of this reaction will be potassium iodate (KIO3) and potassium periodate (KIO4).

### Step 2: Write the balanced chemical equation
The balanced chemical equation for the reaction can be written as follows:
\[ 2 \text{KI} + 3 \text{O}_3 \rightarrow 2 \text{KIO}_3 + \text{KIO}_4 + \text{O}_2 \]

### Step 3: Determine the oxidation states
Next, we need to determine the oxidation states of iodine in the reactants and products:
- In KI, the oxidation state of iodine (I) is +1.
- In KIO3 (potassium iodate), the oxidation state of iodine is +5.
- In KIO4 (potassium periodate), the oxidation state of iodine is +7.

### Step 4: Analyze the changes in oxidation states
From the above oxidation states:
- The oxidation state of iodine increases from +1 in KI to +5 in KIO3 and +7 in KIO4.
- This indicates that iodine is being oxidized.

### Step 5: Conclusion
Thus, when alkaline KI is oxidized by ozone, it forms potassium iodate (KIO3) and potassium periodate (KIO4). Therefore, the correct answer is that KI is oxidized to both KIO3 and KIO4.

### Final Answer
The alkaline KI is oxidized by ozone to potassium iodate (KIO3) and potassium periodate (KIO4).

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