When `H_(2)S` is passed through nitric acid and acidified `KMnO_(4)` solution the product formed is

Options

A. `H_(2)SO_(4)`
B. colloidal sulphur
C. `SO_(2)`
D. plastic sulphur

Explanation

To solve the question "When H₂S is passed through nitric acid and acidified KMnO₄ solution, the product formed is:", we can follow these steps:

### Step 1: Understand the Reactants
- **H₂S (Hydrogen Sulfide)** is a reducing agent.
- **Nitric Acid (HNO₃)** is an oxidizing agent.
- **Acidified KMnO₄** (Potassium Permanganate) is also an oxidizing agent when in acidic medium.

### Step 2: Reaction of H₂S with Nitric Acid
When H₂S reacts with nitric acid, it gets oxidized. The reaction can be represented as:
\[ H₂S + 2HNO₃ \rightarrow S + 2NO + 2H₂O \]
In this reaction, H₂S is oxidized to elemental sulfur (S), and nitric acid is reduced to nitrogen monoxide (NO).

### Step 3: Reaction of H₂S with Acidified KMnO₄
When H₂S is passed through acidified KMnO₄, it also gets oxidized to sulfur. The balanced equation for this reaction is:
\[ 5H₂S + 2KMnO₄ + 3H₂SO₄ \rightarrow 5S + 2MnSO₄ + 8H₂O \]
Again, H₂S is oxidized to sulfur (S), and KMnO₄ is reduced to manganese sulfate (MnSO₄).

### Step 4: Identify the Product
In both reactions, the product formed is sulfur (S). When sulfur is produced in a colloidal form, it is referred to as colloidal sulfur.

### Conclusion
Thus, the product formed when H₂S is passed through nitric acid and acidified KMnO₄ solution is **colloidal sulfur**.

### Final Answer
The correct option is **B: Colloidal Sulfur**.

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