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An inorganic iodide (A) on heating with ...

An inorganic iodide (A) on heating with a solution of KOH gives a gas (B) and a solution of a compound. The gas (B) on ignition in air gives a compound (C ) and water. Copper sulphate is finally reduced to the metal on passing (B) through its solution.
What is true about gas (B) and compound (C ) ?

A

The oxidation number of central atom of gas (B) is `+ IV`

B

The gas (B) produces a black precipitate of methallic sliver with sliver nitrate solution.

C

Compound (C ) dissolves in water forming an acid which with solution hydroxide forms three series of salts.

D

(B) and (C ) both

Text Solution

AI Generated Solution

To solve the question step by step, we need to identify the compounds A, B, and C based on the information provided in the question. ### Step 1: Identify Compound A The question states that an inorganic iodide (A) reacts with KOH to produce a gas (B) and a solution of a compound. A common inorganic iodide that fits this description is phosphonium iodide (PH₄I). ### Step 2: Reaction of A with KOH When phosphonium iodide (PH₄I) is heated with KOH, it produces phosphine gas (B) and potassium iodide (KI) as the solution of a compound. ...
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