What is the ratio of the neutrons present in carbon and silicon atoms with respect to their atomic masses? (Atomic mass of carbon and silicon are 12 and 28 respectively)

Options

A. 7:3
B. 3:7
C. 6:14
D. 14:6

Explanation

To find the ratio of the neutrons present in carbon and silicon atoms with respect to their atomic masses, we can follow these steps:

### Step 1: Identify the Atomic Mass and Atomic Number
- The atomic mass of carbon (C) is 12.
- The atomic mass of silicon (Si) is 28.
- The atomic number of carbon (C) is 6.
- The atomic number of silicon (Si) is 14.

### Step 2: Calculate the Number of Neutrons
The number of neutrons in an atom can be calculated using the formula:
\[ \text{Number of Neutrons} = \text{Mass Number} - \text{Atomic Number} \]

**For Carbon:**
- Mass Number (C) = 12
- Atomic Number (C) = 6
- Neutrons in Carbon (N_C) = 12 - 6 = 6

**For Silicon:**
- Mass Number (Si) = 28
- Atomic Number (Si) = 14
- Neutrons in Silicon (N_Si) = 28 - 14 = 14

### Step 3: Write the Ratio of Neutrons
Now, we can write the ratio of the number of neutrons in carbon to the number of neutrons in silicon:
\[ \text{Ratio} = \frac{N_C}{N_Si} = \frac{6}{14} \]

### Step 4: Simplify the Ratio
To simplify the ratio:
\[ \frac{6}{14} = \frac{3}{7} \]

### Step 5: Final Answer
Thus, the ratio of the neutrons present in carbon and silicon atoms is:
\[ 3 : 7 \]