What is the ratio of the neutrons present in Boron and Fluorine atoms with respect to their atomic mass of 11 and 19

Explanation

To find the ratio of the neutrons present in Boron and Fluorine atoms with respect to their atomic masses of 11 and 19, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Mass and Atomic Number**:
- For Boron (B), the atomic mass is 11 and the atomic number (Z) is 5.
- For Fluorine (F), the atomic mass is 19 and the atomic number (Z) is 9.

2. **Calculate the Number of Neutrons**:
- The number of neutrons (N) in an atom can be calculated using the formula:
\[ N = \text{Mass Number} - \text{Atomic Number} \]
- For Boron:
\[ N_B = 11 - 5 = 6 \]
- For Fluorine:
\[ N_F = 19 - 9 = 10 \]

3. **Set Up the Ratio of Neutrons**:
- Now, we can set up the ratio of the number of neutrons in Boron to the number of neutrons in Fluorine:
\[ \text{Ratio} = \frac{N_B}{N_F} = \frac{6}{10} \]

4. **Simplify the Ratio**:
- Simplifying the fraction:
\[ \frac{6}{10} = \frac{3}{5} \]

5. **Conclusion**:
- Therefore, the ratio of the neutrons present in Boron to Fluorine is:
\[ 3 : 5 \]