What is the ratio of the neutrons present in Nitrogen and Sodium atoms with respect to their atomic mass of 14 and 23

Options

A. 7:12
B. 12:7
C. 14:23
D. 23:14

Explanation

To find the ratio of the neutrons present in Nitrogen and Sodium atoms with respect to their atomic mass, we can follow these steps:

### Step 1: Identify the atomic masses and atomic numbers
- The atomic mass of Nitrogen (N) is 14.
- The atomic mass of Sodium (Na) is 23.
- The atomic number of Nitrogen (N) is 7.
- The atomic number of Sodium (Na) is 11.

### Step 2: Calculate the number of neutrons in Nitrogen
The number of neutrons in an atom can be calculated using the formula:
\[ \text{Number of Neutrons} = \text{Mass Number} - \text{Atomic Number} \]

For Nitrogen:
\[ \text{Neutrons in Nitrogen} = 14 - 7 = 7 \]

### Step 3: Calculate the number of neutrons in Sodium
Using the same formula for Sodium:
\[ \text{Neutrons in Sodium} = 23 - 11 = 12 \]

### Step 4: Write the ratio of neutrons in Nitrogen to Sodium
Now, we can express the ratio of the number of neutrons in Nitrogen to the number of neutrons in Sodium:
\[ \text{Ratio} = \frac{\text{Neutrons in Nitrogen}}{\text{Neutrons in Sodium}} = \frac{7}{12} \]

### Step 5: Simplify the ratio
The ratio of neutrons present in Nitrogen and Sodium is:
\[ 7 : 12 \]

### Final Answer
Thus, the ratio of the neutrons present in Nitrogen and Sodium atoms is **7:12**.

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