A photon of 4000 `A^o` is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of `I_2` ​ molecule is 246.5 kJ/mol is:

Options

A. 8%
B. 12%
C. 17%
D. 25%

Answer

B

Explanation

`P_(4)+3O_(2)overset`("In presence of"`N_(2))toP_(4)O_(6)`. "Here nitrogen acts as diluent".
Note:
"In dry" `O_(2)` "followintg reactions may take place".
`P_(4)+3O_(2)to P_(4)O_(6)`.
`P_(4)O_(6)to P_(4)2O_(2)to P_(4)O_(10)`.
"In moist" `O_(2)` the `P_(4)O_(6)` "gets hydrolysed forming" `H_(3)PO_(3)`.
`P_(4)O_(6)to 4H_(3)PO_(3)`.
"In presence of NaOH".
`P_(4)+3OH^(-)+3H_(2)O to PH_(3)+3H_(2)PO_(2)^(-)`