Amongest `H_(2)O,H_(2)S,H_(2)Se` and `H_(2)` Te the one with highest boiling point is :

Options

A. `H_(2)O` because pf H-bonding .
B. `H_(2)` Te because of higher molecular weight.
C. `H_(2)S` because of H-bonding.
D. `H_(2)Se` because of lower molecular weight.

Explanation

To determine which compound among \( H_2O, H_2S, H_2Se, \) and \( H_2Te \) has the highest boiling point, we can follow these steps:

### Step 1: Identify the Compounds
The compounds we are comparing are:
- Water (\( H_2O \))
- Hydrogen sulfide (\( H_2S \))
- Hydrogen selenide (\( H_2Se \))
- Hydrogen telluride (\( H_2Te \))

### Step 2: Consider Molecular Weights
Generally, boiling points tend to increase with molecular weight. The molecular weights of the compounds are as follows:
- \( H_2O \): 18 g/mol
- \( H_2S \): 34 g/mol
- \( H_2Se \): 81 g/mol
- \( H_2Te \): 130 g/mol

From this, we can see that \( H_2Te \) has the highest molecular weight.

### Step 3: Evaluate Intermolecular Forces
While molecular weight is a factor, we must also consider the types of intermolecular forces present in each compound:
- \( H_2O \) has strong hydrogen bonding due to the highly electronegative oxygen atom.
- \( H_2S, H_2Se, \) and \( H_2Te \) primarily exhibit Van der Waals (dispersion) forces, which are weaker than hydrogen bonds.

### Step 4: Analyze the Effect of Hydrogen Bonding
Hydrogen bonding significantly increases the boiling point of a substance. In the case of water:
- The hydrogen bonds in water create a strong attraction between molecules, requiring more energy (higher temperature) to break these interactions.

### Step 5: Compare the Boiling Points
Considering both molecular weight and the presence of hydrogen bonding:
- Although \( H_2Te \) has the highest molecular weight, the strong hydrogen bonding in \( H_2O \) leads to a higher boiling point than the other compounds.

### Conclusion
Thus, the compound with the highest boiling point among \( H_2O, H_2S, H_2Se, \) and \( H_2Te \) is \( H_2O \) due to its hydrogen bonding.

**Final Answer: \( H_2O \)**

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