Ammonia and red hot `CuO` react to produce :

Options

A. `Cu_(2)O,N_(2),H_(2)`
B. `Cu,H_(2)O,N_(2)`
C. `Cu(OH)_(2),N_(2)`
D. `[Cu(NH_(3))_(4)](OH)_(2)`

Explanation

To solve the question regarding the reaction between ammonia (NH₃) and red hot cupric oxide (CuO), we can follow these steps:

### Step 1: Write the Reactants
Identify the reactants involved in the reaction:
- Ammonia (NH₃)
- Red hot cupric oxide (CuO)

### Step 2: Write the Reaction
Set up the chemical reaction:
\[ \text{2 NH}_3 + \text{3 CuO} \rightarrow \text{3 Cu} + \text{3 H}_2\text{O} + \text{N}_2 \]

### Step 3: Balance the Reaction
Ensure that the number of atoms of each element is the same on both sides of the equation:
- On the left, we have 2 nitrogen (from 2 NH₃), 6 hydrogen (from 2 NH₃), and 3 copper and 3 oxygen (from 3 CuO).
- On the right, we have 2 nitrogen (from N₂), 6 hydrogen (from 3 H₂O), and 3 copper (from 3 Cu).
- The reaction is balanced as written.

### Step 4: Identify the Oxidation States
Determine the oxidation states of the elements involved:
- In NH₃, nitrogen has an oxidation state of -3.
- In N₂, nitrogen has an oxidation state of 0.
- In CuO, copper has an oxidation state of +2.
- In elemental copper (Cu), the oxidation state is 0.

### Step 5: Determine the Oxidation and Reduction
Identify which species is oxidized and which is reduced:
- Ammonia (NH₃) is oxidized to dinitrogen (N₂), as the oxidation state of nitrogen increases from -3 to 0.
- CuO is reduced to copper (Cu), as the oxidation state of copper decreases from +2 to 0.

### Step 6: Write the Final Products
The products of the reaction are:
- Copper (Cu)
- Water (H₂O)
- Dinitrogen (N₂)

### Conclusion
The final products formed when ammonia reacts with red hot cupric oxide are:
- Copper (Cu)
- Water (H₂O)
- Dinitrogen (N₂)

Thus, the answer to the question is:
**Cu, H₂O, and N₂.**

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