When sulphur is boiled with `Na_(2)SO_(3)` solution, the compound formed is :

Options

A. sodium sulphide
B. sodium sulphate
C. sodium persulphate
D. sodium thiosulphate

Explanation

To determine the compound formed when sulfur is boiled with sodium sulfite (Na₂SO₃), we can follow these steps:

### Step 1: Identify the Reactants
We have two reactants: sulfur (S) and sodium sulfite (Na₂SO₃).

### Step 2: Understand the Reaction
When sulfur is boiled with sodium sulfite, a chemical reaction occurs. Sodium sulfite can react with sulfur to form a new compound.

### Step 3: Write the Reaction
The reaction can be represented as:
\[ \text{Na}_2\text{SO}_3 + \text{S} \rightarrow \text{Na}_2\text{S}_2\text{O}_3 \]

### Step 4: Identify the Product
The product formed from this reaction is sodium thiosulfate, which has the chemical formula Na₂S₂O₃.

### Step 5: Conclusion
Thus, when sulfur is boiled with sodium sulfite, the compound formed is sodium thiosulfate (Na₂S₂O₃).

### Final Answer
The compound formed is sodium thiosulfate (Na₂S₂O₃).

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