`{:(,underset(("Oxy acids of phosphoros"))("Column I"),,underset(("Characteristic bonds"))("Column II")),((A),H_(4)P_(2)O_(7),(p),P-P"bond" (s)),((B),H_(4)P_(2)O_(5),(q),P-O-P "bond"(s)),((C),H_(4)P_(2)O_(6),(r),P-H "bond" (s)),((D),(HPO_(3))_(n)("cyclic"),(s),"Three P-OH" bonds):}`

Explanation

To solve the question regarding the oxy acids of phosphorus and their characteristic bonds, we will analyze each compound step by step.

### Step 1: Analyze H₄P₂O₇
1. **Structure**: The basic unit for oxyacids of phosphorus is P=O and P-OH. For H₄P₂O₇, we have two phosphorus atoms.
- Draw two P=O bonds and two P-OH bonds.
- There are three additional oxygen atoms that can be arranged as one P-O and two OH groups.
2. **Bonds**:
- P-P bond: No
- P-O-P bond: Yes (due to the linkage of the two phosphorus atoms)
- P-H bond: Yes (from the OH groups)
- Three P-OH bonds: Yes

**Conclusion for H₄P₂O₇**: Bonds present are P-O-P (Q) and three P-OH (S).

### Step 2: Analyze H₄P₂O₅
1. **Structure**: Similar to H₄P₂O₇, start with two P=O and two P-OH.
- There are five oxygen atoms, so one P-O-P bond can be formed with the remaining oxygen.
2. **Bonds**:
- P-P bond: No
- P-O-P bond: Yes
- P-H bond: Yes
- Three P-OH bonds: No (only two OH groups)

**Conclusion for H₄P₂O₅**: Bonds present are P-O-P (Q) and P-H (R).

### Step 3: Analyze H₄P₂O₆
1. **Structure**: Again, start with two P=O and two P-OH.
- There are two remaining oxygen atoms, which can be used to form two OH groups.
- The two phosphorus atoms can also be linked directly.
2. **Bonds**:
- P-P bond: Yes
- P-O-P bond: No
- P-H bond: Yes (from the OH groups)
- Three P-OH bonds: Yes

**Conclusion for H₄P₂O₆**: Bonds present are P-P (P) and three P-OH (S).

### Step 4: Analyze HPO₃ (cyclic)
1. **Structure**: The cyclic structure can be visualized as a chain of phosphorus and oxygen atoms.
- Each phosphorus atom is connected to oxygen and has OH groups.
2. **Bonds**:
- P-P bond: No
- P-O-P bond: Yes
- P-H bond: Yes (from the OH groups)
- Three P-OH bonds: Yes

**Conclusion for HPO₃**: Bonds present are P-O-P (Q) and three P-OH (S).

### Final Summary of Bonds for Each Compound:
- **H₄P₂O₇**: Q and S
- **H₄P₂O₅**: Q and R
- **H₄P₂O₆**: P and S
- **HPO₃ (cyclic)**: Q and S

### Final Answer:
- For H₄P₂O₇: (Q, S)
- For H₄P₂O₅: (Q, R)
- For H₄P₂O₆: (P, S)
- For HPO₃: (Q, S)