`S_(2)Cl_(2)` hydrolysis slowly to give `HCl`, `SO_(2)` and `S`. State True or False

Explanation

To determine whether the statement "S₂Cl₂ hydrolysis slowly to give HCl, SO₂, and S" is true or false, we can analyze the hydrolysis reaction of disulfur dichloride (S₂Cl₂).

### Step-by-Step Solution:

1. **Identify the Compound**: The compound in question is disulfur dichloride, represented as S₂Cl₂.

2. **Understanding Hydrolysis**: Hydrolysis is a chemical reaction involving water, where water reacts with a compound to form new products. In this case, we are interested in the products formed when S₂Cl₂ reacts with water.

3. **Write the Hydrolysis Reaction**: When S₂Cl₂ undergoes hydrolysis, the expected reaction can be written as:
\[ S_2Cl_2 + H_2O \rightarrow HCl + SO_2 + S \]

4. **Balancing the Reaction**: To ensure the reaction is balanced, we can write the balanced equation. The balanced equation for the hydrolysis of S₂Cl₂ can be represented as:
\[ 2 S_2Cl_2 + 2 H_2O \rightarrow 4 HCl + 3 S + SO_2 \]

5. **Identify the Products**: From the balanced equation, we can see that the products of the hydrolysis are:
- Hydrogen chloride (HCl)
- Sulfur dioxide (SO₂)
- Elemental sulfur (S)

6. **Conclusion**: Since the products of the hydrolysis of S₂Cl₂ include HCl, SO₂, and S, we can conclude that the statement is true.

### Final Answer:
**True**