For the reaction `A+3B hArr 2C+D` initial mole of A is twice that of B . If at equilibrium moles of B and C are equal , then percent of B reacted is

Options

A. `10%`
B. `20%`
C. `40%`
D. `60%`

Answer

4

Explanation

`{:(,A,+,3B,leftrightarrow,2C,+,D,),("initial mole",2a,,a,,0,,0,),("after reaction",2a-x,,a-3x,,2x,,x,),("given that",a-3x=2x,,,,,,,),(,impliesx=a//5,,,,,,,):}`
`%` of B reacted `=3x//a xx 100=3//5xx100=60%`