In the reaction
`4A + 2B + 3C to A_(4)B_(2) C_(3)`, what will be the number moles of product formed starting from one mole of A, 0.6 moles of B and 0.72 moles of C?

Options

A. `0.5`
B. `0.6`
C. `0.48`
D. `4.64`

Answer

3

Explanation

`{:(,4A,+,2B,+,3C,rarr,A_(4)B_(2)C_(3)),("Initial mole",2,,1.2,,1.44,,0),("final mole",,,,,0,,0.48):}`
C is limiting reagent.
`:.` moles of `A_(4)B_(2)C_(3)` is `0.48`,