The correct order of boiling point is:

Options

A. `H_(2)O lt H_(2)S lt H_(2)Se lt H_(2)Te`
B. `H_(2)O gt H_(2)Se gt H_(2)Te gt H_(2)S`
C. `H_(2)O gt H_(2)S gt H_(2)Se gt H_(2)Te`
D. `H_(2)O gt H_(2)Te gt H_(2)Se gt H_(2)S`

Answer

4

Explanation

`(i) H_(2)O` has highest boiling point because of `H-` bonding.
`(ii)` Boiling point also depends on the magnitude of van der Waal's force of attraction, which in turns depends on molecular weight of the compounds. Thus the correct order is `H_(2)OgtH_(2)TegtH_(2)SegtH_(2)S`.