The correct order of bond angles between bond pair`-`bond pair of electrons ( biggest first ) in `overset(+)(N)O_(2),H_(2)O,C Cl_(2)` and `BF_(3)` is :

Options

A. `overset(+)(N)O_(2)gtBF_(3)gtH_(2)OgtC Cl_(4)`
B. `BF_(3)gtoverset(+)(N)O_(2)gtH_(2)OgtC Cl_(4)`
C. `overset(+)(N)O_(2)gtBF_(3)gtC Cl_(4)gtH_(2)O`
D. `BF_(3)gtH_(2)Ogtoverset(+)(N)O_(2)gtC Cl_(4)`

Explanation

To determine the correct order of bond angles between bond pair-bond pair of electrons in the molecules \( \overset{+}{N}O_2, H_2O, Cl_2, \) and \( BF_3 \), we will analyze each molecule step by step.

### Step 1: Analyze \( \overset{+}{N}O_2 \)
- **Structure**: The nitronium ion \( \overset{+}{N}O_2 \) has a linear structure due to its sp hybridization.
- **Bond Angle**: The bond angle is approximately \( 180^\circ \).

### Step 2: Analyze \( BF_3 \)
- **Structure**: Boron trifluoride \( BF_3 \) has a trigonal planar structure due to its sp² hybridization.
- **Bond Angle**: The bond angle is approximately \( 120^\circ \).

### Step 3: Analyze \( Cl_2 \)
- **Structure**: Dichlorine \( Cl_2 \) is a diatomic molecule and does not have a traditional bond angle as it consists of only two atoms.
- **Bond Angle**: The bond angle is effectively \( 180^\circ \) (similar to \( N_2 \)), but since it is not a polyatomic molecule, we will not consider it in the order of angles.

### Step 4: Analyze \( H_2O \)
- **Structure**: Water \( H_2O \) has a bent shape due to its sp³ hybridization and the presence of lone pairs on oxygen.
- **Bond Angle**: The bond angle is approximately \( 104.5^\circ \).

### Step 5: Compile the Bond Angles
Now, we will summarize the bond angles we have determined:
- \( \overset{+}{N}O_2 \): \( 180^\circ \)
- \( BF_3 \): \( 120^\circ \)
- \( H_2O \): \( 104.5^\circ \)
- \( Cl_2 \): \( 180^\circ \) (not considered in the order)

### Step 6: Determine the Correct Order
From the angles calculated, we can arrange them in descending order:
1. \( \overset{+}{N}O_2 \): \( 180^\circ \)
2. \( Cl_2 \): \( 180^\circ \) (but we will consider \( N_2 \) for the order)
3. \( BF_3 \): \( 120^\circ \)
4. \( H_2O \): \( 104.5^\circ \)

Thus, the final order of bond angles from largest to smallest is:
\[ \overset{+}{N}O_2 \approx Cl_2 > BF_3 > H_2O \]

### Final Answer
The correct order of bond angles between bond pair-bond pair of electrons (biggest first) in \( \overset{+}{N}O_2, H_2O, Cl_2, \) and \( BF_3 \) is:
\[ \overset{+}{N}O_2 > Cl_2 > BF_3 > H_2O \]