In which of the following compounds B atoms are in `sp^(2)` and `sp^(3)` hybridisation states ?

Options

A. Borax
B. Diborane
C. Borazole
D. All

Explanation

To determine the hybridization states of boron (B) atoms in the given compounds, we will analyze the structures of each compound step by step.

### Step 1: Analyze Borax (Na₂B₄O₇·10H₂O)
1. **Formula and Structure**: Borax has the formula Na₂B₄O₇·10H₂O. The structure can be represented as B₄O₅(OH)₄²⁻.
2. **Identify Hybridization**: In the structure, there are two types of boron atoms:
- Two boron atoms are involved in forming bonds with oxygen and hydroxyl groups, leading to **sp² hybridization**.
- The other two boron atoms are connected to four other atoms (two hydroxyl and two oxygen), leading to **sp³ hybridization**.
3. **Conclusion for Borax**: Borax contains both sp² and sp³ hybridized boron atoms.

### Step 2: Analyze Diborane (B₂H₆)
1. **Formula and Structure**: Diborane has the formula B₂H₆. The structure consists of two boron atoms bonded to hydrogen atoms.
2. **Identify Hybridization**: In diborane, each boron atom forms four bonds (two terminal B-H bonds and two bridging B-H bonds). This results in:
- **sp³ hybridization** for both boron atoms due to the tetrahedral geometry around each boron.
3. **Conclusion for Diborane**: Diborane contains only sp³ hybridized boron atoms.

### Step 3: Analyze Borazole (B₃N₃H₆)
1. **Formula and Structure**: Borazole, also known as borazine, has the formula B₃N₃H₆. Its structure resembles that of benzene.
2. **Identify Hybridization**: In borazole, each boron atom is bonded to nitrogen and hydrogen atoms. The bonding involves:
- **sp² hybridization** for all boron atoms, as they form planar structures similar to benzene.
3. **Conclusion for Borazole**: Borazole contains only sp² hybridized boron atoms.

### Final Conclusion
- **Borax**: Contains both sp² and sp³ hybridized boron atoms.
- **Diborane**: Contains only sp³ hybridized boron atoms.
- **Borazole**: Contains only sp² hybridized boron atoms.

Thus, the correct answer is **Borax** for the presence of both sp² and sp³ hybridized boron atoms.

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