How many ions are produced from the comp...

How many ions are produced from the complex, `[Co(NH_(3))_(6)]CI_(2)` in solution ?

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The correct Answer is:

`[Pt(NH_(3))_(2)(SCN)_(2)]-` cis and trans isomers `=2`.
`[Pt(NH_(3))_(2)(NCS)(SCN)]-` cis and trans isomers `=2`.
`[Pt(NH_(3))_(2)(NCS)_(2)-` cis and trans isomers `=2`.
The complex is square planar `,` so it does not have a pair of enantiomer on account of the presence of plane of symmetry.

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