What are the products formed in the reaction of xenon hexafluoride with silicon dioxide ?

Options

A. `XeSiO_(4)+HF`
B. `XeF_(2)+SiF_(4)`
C. `XeOF_(4)+SiF_(4)`
D. `XeO_(3)+SiF_(2)`

Explanation

To determine the products formed from the reaction of xenon hexafluoride (XeF6) with silicon dioxide (SiO2), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are xenon hexafluoride (XeF6) and silicon dioxide (SiO2).

2. **Understand the Reaction**:
Xenon hexafluoride is known to act as a fluorinating agent. It can react with silicon dioxide to fluorinate it.

3. **Write the Balanced Chemical Equation**:
The balanced chemical equation for the reaction can be written as:
\[ 2 \, \text{XeF}_6 + \text{SiO}_2 \rightarrow 2 \, \text{XeOF}_4 + \text{SiF}_4 \]
This indicates that two moles of xenon hexafluoride react with one mole of silicon dioxide to produce two moles of xenon oxytetrafluoride (XeOF4) and one mole of silicon tetrafluoride (SiF4).

4. **Identify the Products**:
From the balanced equation, we can see that the products formed are:
- Xenon oxytetrafluoride (XeOF4)
- Silicon tetrafluoride (SiF4)

5. **Conclusion**:
Therefore, the products formed from the reaction of xenon hexafluoride with silicon dioxide are 2 moles of XeOF4 and 1 mole of SiF4.

### Final Answer:
The products formed in the reaction of xenon hexafluoride with silicon dioxide are:
- 2 XeOF4
- 1 SiF4