A photon of 5000 `A^o` is used to break the iodine molecule, then the % of energy converted to the K.E. of iodine atoms if bond dissociation energy of `I_2` ​ molecule is 155.5 kJ/mol is:

Options

A. 34.8%
B. 30%
C. 15%
D. 74%

Answer

A

Explanation

Rate of governed by slowest step
`A+B overset(k_(1))rarr AB+B`
`r=k_(1)[A][B_(2)]" "……(i)`
From `A_(2)overset(k_(c))hArrA+A`
`k_(c)=([A]^(2))/([A_(2)])" ".....(ii)`
`[A]=sqrt(k_(c))[A_(2)]^(1//2)`
`r=k_(1)sqrt(k_(c))[A_(2)]^(1//2)[B_(2)]" order is "=(1)/(2)+1=(3)/(2)`