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Total number of geometrical isomers for ...

Total number of geometrical isomers for the complex `[RhBr(H_(2)O)(PPh_(3))(NH_(3))]` is `:`

A

2

B

3

C

4

D

1

Text Solution

Verified by Experts

The correct Answer is:
2
`[M (` abcd`)]` complex is square planar, so will have 3 geometrical isomers.
`(i)(`a Tb`) ( ` c T d `),(ii)(` a T c `) (` b T d`) , (iii)(` a T d `) ( ` b T c `)`
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