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Which one of the following is not a hydr...

Which one of the following is not a hydrolysis product of `XeF_(4)` with excess water ?

A

`Xe`

B

`XeO_(3)`

C

`O_(2)`

D

`XeO_(2)F_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which one of the following is not a hydrolysis product of \( \text{XeF}_4 \) with excess water, we need to analyze the hydrolysis reaction of \( \text{XeF}_4 \). ### Step-by-Step Solution: 1. **Identify the Reaction**: The hydrolysis of \( \text{XeF}_4 \) with excess water can be represented as: \[ \text{XeF}_4 + 2 \text{H}_2\text{O} \rightarrow \text{Xe} + \text{XeO}_3 + 4 \text{HF} \] This reaction indicates that \( \text{XeF}_4 \) reacts with water to produce xenon gas (\( \text{Xe} \)), xenon trioxide (\( \text{XeO}_3 \)), and hydrofluoric acid (\( \text{HF} \)). 2. **List the Products**: From the reaction, we can identify the products: - \( \text{Xe} \) (gaseous xenon) - \( \text{XeO}_3 \) (xenon trioxide) - \( \text{HF} \) (hydrofluoric acid) 3. **Identify the Options**: Now, we need to check the options provided in the question. The options typically include: - \( \text{Xe} \) - \( \text{XeO}_3 \) - \( \text{HF} \) - \( \text{XeO}_2F_2 \) (xenon difluoride oxide) 4. **Determine the Incorrect Product**: Among the products formed from the hydrolysis of \( \text{XeF}_4 \), \( \text{XeO}_2F_2 \) is not produced. The other three products (\( \text{Xe} \), \( \text{XeO}_3 \), and \( \text{HF} \)) are indeed formed during the reaction. 5. **Conclusion**: Therefore, the answer to the question "Which one of the following is not a hydrolysis product of \( \text{XeF}_4 \) with excess water?" is: \[ \text{XeO}_2F_2 \]

To determine which one of the following is not a hydrolysis product of \( \text{XeF}_4 \) with excess water, we need to analyze the hydrolysis reaction of \( \text{XeF}_4 \). ### Step-by-Step Solution: 1. **Identify the Reaction**: The hydrolysis of \( \text{XeF}_4 \) with excess water can be represented as: \[ \text{XeF}_4 + 2 \text{H}_2\text{O} \rightarrow \text{Xe} + \text{XeO}_3 + 4 \text{HF} ...
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