An alpha particle after passing through a potential difference of 4×`10^6` volt falls on a silver foil. The atomic number of silver is 47. The K.E. of the α-particle at the time of falling on the foil is:

Options

A. 5.6×`10^(−13)`J
B. 12.8×`10^(−13)`J
C. 8.6×`10^(−13)`J
D. 4.8×`10^(−13)`J

Answer

3

Explanation

`(i)` It shows ionisation, linkage as well as geometrical isomerism.
`(ii) [Co(NH_(3))_(4)(NO_(2))_(3)]^(+)` is diamagnetic inner orbital complex with `t_(2g)^(6)` electron configuration.
`(iv) [V(CO)_(6)]^(-)` is diamagnetic with `t_(2g)^(6)` electron configuration.